Mixing Mogas with 100ll
Planning a cross country and one of the fuel stops has 90 octane mogas. How much 100ll should I add per gallon to bring the octane up to 91? Trying to use the least amount of 100ll as possible.
Thanks
Planning a cross country and one of the fuel stops has 90 octane mogas. How much 100ll should I add per gallon to bring the octane up to 91? Trying to use the least amount of 100ll as possible.
Thanks
by Eric Page » 4 hours ago
Since there are 10 octane points between the two fuels, every 10% of the mixture that's 100 octane will raise the final octane by one point. Thus, to get 91 octane you need 100LL to be 10% of the mixture. Proof below.
Formula: (Fuel A Octane x Fuel A %) + (Fuel B Octane x Fuel B %) = Desired Octane
If n represents the percentage of fuel that is 100 octane, then the percentage of 90 octane is (1 - n).
90 x (1 - n) + (100 x n) = 91 [re-write formula]
90 - 90n + 100n = 91 [expand]
90 + 10n = 91 [simplify]
10n = 1 [subtract 90 from both sides]
n = 0.1 [divide both sides by 10]
∴ 100 octane = 10% of mixture
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