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Planning a cross country and one of the fuel stops has 90 octane mogas. How much 100ll should I add per gallon to bring the octane up to 91? Trying to use the least amount of 100ll as possible.

Thanks

  • Re: Mixing Mogas with 100ll

    by » 4 hours ago


    Since there are 10 octane points between the two fuels, every 10% of the mixture that's 100 octane will raise the final octane by one point.  Thus, to get 91 octane you need 100LL to be 10% of the mixture.  Proof below.

     

    Formula: (Fuel A Octane x Fuel A %) + (Fuel B Octane x Fuel B %) = Desired Octane

    If n represents the percentage of fuel that is 100 octane, then the percentage of 90 octane is (1 - n).

    90 x (1 - n) + (100 x n) = 91  [re-write formula]

    90 - 90n + 100n = 91  [expand]

    90 + 10n = 91  [simplify]

    10n = 1  [subtract 90 from both sides]

    n = 0.1  [divide both sides by 10]

    ∴ 100 octane = 10% of mixture


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